The firts terms a of an A.P is equal to twice the common difference d.Find, in term of d, the 5th term of the A.P.
so a = 2d
term(5) = a + 4d
= 2d + 4d = 6d
270000\3000
To find the 5th term of the arithmetic progression (A.P), we need to know the first term (a) and the common difference (d). Let's denote the first term as a and the common difference as d.
According to the given information, the first term a is equal to twice the common difference d: a = 2d.
The formula to find the nth term (Tn) of an A.P is:
Tn = a + (n - 1)d
Substitute the value of a from the given information into the formula:
Tn = 2d + (n - 1)d
To find the 5th term (T5), substitute n = 5 into the formula:
T5 = 2d + (5 - 1)d
Simplify the expression:
T5 = 2d + 4d
T5 = 6d
Therefore, the 5th term of the A.P in terms of d is 6d.