The scores on the Advanced Algebra final exam are approximately normally distributed with a mean of 150 and a standard deviation of 15. What percentage of the students who took the test scored above 180?(1 point) Responses 2.5% 2.5% 2.35% 2.35% 16% 16% 15.85%

To find the percentage of students who scored above 180, we need to find the z-score for 180 and then use a standard normal distribution table.

First, calculate the z-score:
z = (X - μ) / σ
z = (180 - 150) / 15
z = 2

Now, look up the z-score of 2 in the standard normal distribution table. The area to the right of z = 2 is approximately 0.0228 or 2.28%.

Therefore, approximately 2.28% of the students who took the test scored above 180. Since this is not one of the given answer choices, the closest option is 2.5%.