Question

The scores on the Advanced Algebra final exam are approximately normally distributed with a mean of 150 and a standard deviation of 15. What percentage of the students who took the test scored above 180?(1 point) Responses 2.5% 2.5% 15.85% 15.85% 2.35% 2.35% 16%

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the percentage of students who scored above 180, we need to find the z-score corresponding to a score of 180 and then find the percentage of the area under the normal curve that lies above that z-score.

First, calculate the z-score:

z = (x - mean) / standard deviation
z = (180 - 150) / 15
z = 2

Next, find the percentage of the area under the normal curve that lies above a z-score of 2. Using a standard normal distribution table or calculator, we can find that the percentage is approximately 2.28%.

Therefore, the percentage of students who scored above 180 is approximately 2.28%.