Question

the scores on the Advanced Algebra final exam are approximately normally distributed with a mean of 150 and a standard deviation of 15. What percentage of the students who took the test scored above 180?

A)2.35%
B)15.85%
C)16%
D)2.5%

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the percentage of students who scored above 180, we need to find the z-score for 180 and then find the area to the right of that z-score on the standard normal distribution table.

The z-score formula is given by:
z = (X - μ) / σ
where X is the score, μ is the mean, and σ is the standard deviation.

Plugging in the values:
z = (180 - 150) / 15
z = 30 / 15
z = 2

Looking up the z-score of 2 on the standard normal distribution table, we find that the area to the right of 2 is approximately 0.0228, or 2.28%.

Therefore, the percentage of students who scored above 180 is approximately 2.28%, which is closest to option A) 2.35%.