Solve the following word problem the air temperature at 9 AM is -15.8 Celsius air temperature at noon is -1.6°C. What is the change in the temperature during these three hours right and solve an equation to show your answers and explain what your answer me.
To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.
Let's denote the initial temperature at 9 AM as T₁ and the final temperature at noon as T₂.
Given:
T₁ = -15.8°C (air temperature at 9 AM)
T₂ = -1.6°C (air temperature at noon)
To find the change in temperature, we subtract T₁ from T₂:
Change in temperature = T₂ - T₁
Change in temperature = (-1.6°C) - (-15.8°C)
To subtract a negative number, we change the operation to addition:
Change in temperature = (-1.6°C) + (15.8°C)
Now, we can simplify the equation:
Change in temperature = 14.2°C
Therefore, the change in temperature during these three hours is 14.2 degrees Celsius. The equation used to find this answer is explained step by step, taking into account the initial and final temperatures.
To find the change in temperature during the three hours between 9 AM and noon, we can subtract the initial temperature from the final temperature.
Let's define:
Initial temperature at 9 AM = A (in degrees Celsius)
Final temperature at noon = B (in degrees Celsius)
Change in temperature = B - A
Given:
A = -15.8°C
B = -1.6°C
Substituting the given values into the equation, we have:
Change in temperature = (-1.6) - (-15.8)
To subtract a negative number, we can change the sign of the number being subtracted and then add. So, we have:
Change in temperature = -1.6 + 15.8
Now, let's solve the equation step by step:
Change in temperature = 15.8 - 1.6
Change in temperature = 14.2°C
Therefore, the change in temperature during the three hours is an increase of 14.2 degrees Celsius.