# Solve the following word problem. The air temperature at 9 a.m. is -5.8 degrees Celsius. The air temperature at noon is -1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.

## To find the change in temperature, we subtract the initial temperature from the final temperature.

Change in temperature = Final temperature - Initial temperature

Therefore, the change in temperature is (-1.6) - (-5.8) = 4.2 degrees Celsius.

The answer means that the temperature increased by 4.2 degrees Celsius during the three hours between 9 a.m. and noon.

## Can you simplify

## To find the change in temperature during the three hours from 9 a.m. to noon, we can subtract the initial temperature from the final temperature.

The initial temperature at 9 a.m. is -5.8 degrees Celsius.

The final temperature at noon is -1.6 degrees Celsius.

To find the change in temperature, we subtract the initial temperature from the final temperature:

Change in temperature = Final temperature - Initial temperature

Let's substitute the given values into the equation:

Change in temperature = (-1.6) - (-5.8)

Now, we need to simplify the equation:

Change in temperature = -1.6 + 5.8

By adding -1.6 and 5.8, we get:

Change in temperature = 4.2

The change in temperature during these three hours is 4.2 degrees Celsius.

This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.

## To find the change in temperature during the three hours, we need to subtract the initial temperature from the final temperature.

First, let's assign variables for the temperatures:

Initial temperature at 9 a.m. = T1 = -5.8 degrees Celsius

Final temperature at noon = T2 = -1.6 degrees Celsius

Now, we can write the equation to show the change in temperature:

Change in temperature = T2 - T1

Substituting the values:

Change in temperature = (-1.6) - (-5.8)

To subtract a negative number, we can rewrite the equation as:

Change in temperature = (-1.6) + 5.8

Now we can add these two numbers:

Change in temperature = 4.2 degrees Celsius

Therefore, the change in temperature during the three hours is 4.2 degrees Celsius.

This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.