# Solve the following word problem. The air temperature at 9 a.m. is −5.8 degrees Celsius. The air temperature at noon is −1.6 degrees Celsius. What is the change in the temperature during these three hours? Write and solve an equation to show your answer. Then explain what your answer means.(4 points)

## To find the change in temperature during these three hours, we need to subtract the initial temperature from the final temperature.

Let's call the initial temperature at 9 a.m. T1 and the final temperature at noon T2.

T1 = -5.8 degrees Celsius
T2 = -1.6 degrees Celsius

The change in temperature during these three hours is T2 - T1.

Change in temperature = (-1.6) - (-5.8)
Change in temperature = -1.6 + 5.8
Change in temperature = 4.2 degrees Celsius

The change in the temperature during these three hours is 4.2 degrees Celsius. This means that the temperature increased by 4.2 degrees Celsius between 9 a.m. and noon.

## To find the change in temperature during these three hours, we need to subtract the temperature at 9 am from the temperature at noon. Let's denote the change in temperature as ΔT.

The temperature at 9 am is -5.8 degrees Celsius, and the temperature at noon is -1.6 degrees Celsius. Therefore, the equation for the change in temperature is:

ΔT = (-1.6) - (-5.8)

To simplify, we can rewrite the equation as:

ΔT = -1.6 + 5.8

Solving this equation, we get:

ΔT = 4.2

The change in temperature during these three hours is 4.2 degrees Celsius.

This means that the temperature has increased by 4.2 degrees Celsius from 9 am to noon.

## To find the change in temperature during the three-hour period, we need to subtract the initial temperature at 9 a.m. from the temperature at noon.

First, we define the initial temperature as -5.8 degrees Celsius and the temperature at noon as -1.6 degrees Celsius.

To calculate the change in temperature, we can subtract the initial temperature from the final temperature:

Change in temperature = Final temperature - Initial temperature

Change in temperature = (-1.6) - (-5.8)
= -1.6 + 5.8
= 4.2

Therefore, the change in temperature during the three-hour period is 4.2 degrees Celsius.

This means that the temperature increased by 4.2 degrees Celsius from 9 a.m. to noon.