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AJ L
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AJ L
Answers (419)
I answered this problem on Brainly for you. I'm @goddessboi there
A = πr^2 A = π(5)^2 A = π(25) A = 25π in^2
Since our p-value is less than the assumed critical value of α=0.05, it is very likely that the null hypothesis is true and that the alternate hypothesis is not true. This means the null hypothesis fails to be rejected, but the alternate hypothesis is
We observe that the test is right-tailed since the alternate hypothesis suggests that the true mean might be greater than the null hypothesis of 100. According to the z-table, a z-score of z=2.17 corresponds to a p-value of p=0.9850 Because the test is
Um, wouldn't that statement contradict your previous statement?
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A circle is measured 360 degrees, so dividing it into 5 equal parts means that each sector is 360/5 = 72 degrees. This means that 4 parts will measure 72*4 = 288 degrees.
I'd agree with B
I'd agree with your answer. If something is tangible, it means it is susceptible to change, which can include touch.
I'm a senior in high school, and have also been doing some hard problems for a while (have knowledge in Calculus II material + Statistics and below), so I come here once in a while to help. Been around for maybe 2-3 years.
This is the problem with Jiskha sometimes. People don't even bother to finish their questions...
@oobleck I think you forgot the x at the beginning of the volume since volume is not in square units.
V = x(2x²+x+5)
Let me redo this problem (I accidentally did differentiation instead of integration lol): Part A: Well, if you integrate acceleration, you get velocity, so this part is simple: ∫[e^(t/2)]dt = 2e^(t/2)+C At t=0, the velocity is -4 m/sec, so we need to
Part A: Well, if you integrate acceleration, you get velocity, so this part is simple: ∫[e^(t/2)]dt = (1/2)e^(t/2)+C At t=0, the velocity is -4 m/sec, so we need to solve for the constant C to complete the velocity function v(t): (1/2)e^(0/2) + C = -4
24^(1/3) = 8^(1/3) * 3^(1/3) = 2 * 3^(1/3) = 2cbrt(3)
Just multiply the molar mass of gold with the number of moles of gold to cancel out the moles in the denominator: 0.147 mol * 196.97 g/mol = 28.95459 grams
Welp, you tell me. What happens when resources are scarce? Would there be enough for every organism in the food chain? Who would survive and who would die out?
Since order doesn't matter, if one student can go to any seat, then there are 3 ways to sit a student in one chair. Thus, there are 3*3*3=27 ways to arrange 3 students into 3 chairs by the Fundamental Counting Principle.
n! = n(n-1)(n-2)...3*2*1 (n-k-1)! = (n-k-1)(n-k-2)(n-k-3)...*3*2*1 Thus, n!/(n-k-1)! = n(n-1)...(n-k)
Welp, what are the coordinates of the triangle?
x^2+5x+6 has factors of x+3 and x+2, so if their roots (x = -3, -2) are plugged into the polynomial in question, we should get 0 for both roots by the Remainder Theorem: x^4 + 5x^3 + 2x^2 – 20x – 24 (-3)^4 + 5(-3)^3 + 2(-3)^2 - 20(-3) - 24 81 - 135 +
What do you think?
You have to be in RADIANS, not degrees
Ah, I see where the OP went wrong. The correct answer is supposed to be 0.009 since -sin(π/3) * -0.01 = 0.00866 ≈ 0.009 @oobleck looks like you forgot to make the differential negative
-6x+5y=1 6x+4y=-10 ________ 9y=-9 y=-1 6x+4(-1)=-10 6x-4=-10 6x=-6 x=-1 So x=-1 and y=-1
I feel like I've seen this before lol
Be very careful
Remember that 5/(11π) is the rate that the diameter is decreasing! If it decreased at a rate of -5/(11π), then it's increasing at a rate of 5/(11π)!
Given: d(SA)/dt = 10cm^2/min d(d)/dt = ? d = 11 SA = 4πr^2 = 4π(d/2)^2 = π*d^2 Calculation: SA = π*d^2 d(SA)/dt = 2πd[d(d)/dt] 10 = 2π(11)[d(d)/dt] 10 = 22π[d(d)/dt] 5/(11π) = d(d)/dt Looks like your mistake was the negative there somehow lol
This is very weird. Not sure how to help you since 1.83*10^-4 is 0.000183 as a decimal
Since we are dealing with 2 samples that both have small sample sizes, then we are looking for the t-statistic. Assuming the conditions are valid for this problem, we first find the difference between the two averages, so 1.2-1.15=0.05 Next, we find the
I made substitutions in my answer to make it simpler, but I guess both answers are fine. It depends.
tan(x-y)=y/(1+x^2) sec^2(x-y)*(1-dy/dx) = [(y+x^2y)(dy/dx)-(y)(2x)] /[(1+x^2)^2] sec^2(x-y)*(1-dy/dx) = (dy/dx)[1/(1+x^2)] - 2xy/[(1+x^2)^2] (dy/dx)[sec^2(x-y) + 1/(1+x^2)^2] = sec^2(x-y) + 2xy/[(1+x^2)^2] dy/dx = [(sec^2(x-y) + 2xy/(1+x^2)^2)] /
But it also might not be either axis! Perhaps the lines x=5 or y=4 for instance. That volume would change.
Given Information: dr/dt = 5 cm/s h = 2r r = 8 V = (π*r^2*h)/3 --> V = (π*r^2*2r)/3 --> V = (2πr^3)/3 dV/dt = ? Calculation: V = (2πr^3)/3 dV/dt = 2πr^2(dr/dt) dV/dt = 2π(8)^2(5) dV/dt = 10π(64) dV/dt = 640π cm^3/s So, the volume of the cone
The area of the region is pretty simple since it's a triangle. If you graph it, it has endpoints at (3,0) and (0,3), telling us the dimensions of the triangle. Thus, the area of the region is (3*3)/2 = 9/2 = 4.5 square units You don't give a revolution
What are your guesses for each question?
Just use the distance formula like @oobleck showed
Hope this explanation helped!
Since we know that the 13th term is -30, use the explicit formula for an arithmetic sequence, plugging in n=13 and solving for a1: a(n) = a1+(n-1)d a(13) = a1+(13-1)d -30 = a1+12d a1 = -30-12d Since the 7th and 10th terms add up to 12, do the same thing:
$25 - ($16 + $4.56) = $25 - $20.56 = $4.44
This isn't an equation. Please fix your question.
Correction: 1+tan^2θ = sec^2θ
Assuming you mean (1 - cos^2 θ)(1 -tan^2 θ) = tan^2 θ: There are two Pythagorean Identities that can be applied here, 1+cos^2 θ = sin^2 θ, and 1 - tan^2 θ = sec^2 θ. Thus, we have (sin^2 θ)(sec^2 θ) = tan^2 θ Since sec^2 θ = 1/cos^2 θ, then we
Post your questions and your attempts to solve them
14x+1
Here's a graph of the circle: ttps://www.desmos.com/calculator/jjdnddjczx
Write x/2+y/4=1/2 as 2x+y=2, thus, y=2-2x: x/3 - y/5 = 1/9 5x - 3y = 15/9 5x - 3(2-2x) = 15/9 5x - 6 + 6x = 15/9 11x - 6 = 15/9 11x = 69/9 x = 69/99 x = 23/33 y = 2-2x = 2-2(23/33) = 2-(46/33) = 66/33-46/33 = 20/33 Therefore, x=23/33 and y=20/33
Let C be the number of children tickets and A be the number of adult tickets. 6A + 4C = 224 A = 2C 6A + 4C = 224 6(2C) + 4C = 224 12C + 4C = 224 16C = 224 C = 14 Thus, A = 2C = 2(14) = 28 This means that there were 14 children tickets and 28 adult tickets.
