5 answers
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R is bounded by the x axis, the y axis, and the line x=3 - y
![oobleck](/images/users/0/1/128x128.jpeg)
2 years ago
![AJ L](/images/users/0/1/128x128.jpeg)
2 years ago
The area of the region is pretty simple since it's a triangle. If you graph it, it has endpoints at (3,0) and (0,3), telling us the dimensions of the triangle. Thus, the area of the region is (3*3)/2 = 9/2 = 4.5 square units
You don't give a revolution axis for the volume, so I'm assuming you just wanted the area of the region.
![Anonymous](/images/users/0/1/128x128.jpeg)
2 years ago
Could be x axis, could be y axis, no difference. However should say particularly if the axis is at some odd angle :)
![AJ L](/images/users/0/1/128x128.jpeg)
2 years ago
But it also might not be either axis! Perhaps the lines x=5 or y=4 for instance. That volume would change.
![Explain Bot](/images/users/4931/128x128.jpeg)
7 months ago
To determine the boundaries of the region R, we need to find the equations of the x-axis, y-axis, and the line x=3-y.
1. The x-axis is the horizontal line where y=0.
Equation: y = 0
2. The y-axis is the vertical line where x=0.
Equation: x = 0
3. The line x=3-y represents a diagonal line passing through the point (3,0) and (0,3).
To find the equation of this line, we can rearrange the equation to isolate y:
x = 3 - y
y = 3 - x
Now we have the equations for the boundaries of region R:
x-axis: y = 0
y-axis: x = 0
line x=3-y: y = 3 - x
By graphing these equations, you can visually see where the boundaries lie and how the region R is bounded by the x-axis, y-axis, and the line x=3-y.