Question

There were some grapefruits and durians in Container A and Container B. In Container A, the ratio of the grapefruits to the number of durians was 3:1. In Container B, the ratio of the number of grapefruits to the number of durians was 3:2. There were 2 times as many fruits in Container A as in Container B. After 56 durians were put into Container B, the ratio of the number of grapefruits to the number of durians in Container B became 1:2. How many fruits are there in Container A at the end?

Answer 1

What are your answers?

What do you think the answer is?
How did you get the answer you think it is if you think you know what the answer is?

Answer 2

For the first question I meant the answer choices

Answer 3

in container A we start with x durians and 3x grapefruits

in container B we start with 2y durians and 3y grapefruits
Now, what are we told?
x+3x = 2(2y+3y)
3y = 1/2 (2y+56)
solve to get
x = 35, y=14
So A had 4x = 140 fruits at the start

Answer 4

Are you like, in high school or something (Oobleck)?

You seem to know everything to every question.

Answer 5

I studied mathematics in college 50 years ago.

I know how to solve these problems because I have already done hundreds just like them.

Answer 6

Oh:0

Answer 7

I'm a senior in high school, and have also been doing some hard problems for a while (have knowledge in Calculus II material + Statistics and below), so I come here once in a while to help. Been around for maybe 2-3 years.

Answer 8

And I studied math 60 years ago, taught senior highschool math for 35

years. Been retired for 25 years, still love math.
I think I still know the stuff, but lately I have been known to make some
silly mistakes, but with thanks to oobleck and "anonymous" , most are caught.

Answer 9

[AI-generated answer — Explain Bot]

To solve this problem, we can follow these steps:

Step 1: Let's represent the number of grapefruits in Container A as 3x and the number of durians in Container A as x. This is because the ratio of grapefruits to durians in Container A is 3:1.

Step 2: From the given information, we can set up the following equation:

3x = 2(3x + 56)
Simplifying the equation, we get:
3x = 6x + 112
Rearranging the terms, we get:
3x - 6x = 112
-3x = 112
Dividing both sides by -3, we get:
x = -112/3

Step 3: Since the number of fruits cannot be negative, we discard the negative value of x. Therefore, there are no fruits in Container A.

So, there are no fruits in Container A at the end.