Charlotte is training for a marathon. Right now she is 21km from home. She is running toward home at a rate of 10 km per hour.(Let x=time(in hours); y=distance from home (in km).) [lHint: Charlottle's distance from home is decreasing.]
There is no question in your post.
Do you want the equation for the distance she is from home?
then
y = -10x + 21 , where x and y are as defined
can u help me put it in a table format
To find out how long it will take for Charlotte to reach home, we can use the formula for speed: speed = distance / time.
In this case, we know Charlotte's speed is 10 km/h, and she is running towards home, so the distance is decreasing. Therefore, we need to calculate the time it will take for Charlotte to go from 21 km to 0 km.
Let's denote x as the time in hours and y as the distance from home in km at a certain time.
Given that Charlotte is running towards home at a rate of 10 km/h, we can create the equation:
y = 21 - 10x
To find the time it will take to reach home (when y = 0), we need to solve for x:
0 = 21 - 10x
To isolate x, we subtract 21 from both sides:
10x = 21
Finally, we divide both sides by 10:
x = 21 / 10
Simplifying further, we can express the time it will take for Charlotte to reach home as:
x = 2.1 hours, or 2 hours and 6 minutes.
Therefore, it will take Charlotte approximately 2 hours and 6 minutes to reach home.