Determine two pairs of polar coordinates for (3,-3) when 0°<θ<360°
how about
(3√2 , 315°) or 3√2, - 45°) or (-3√2 , 135°) ?
why are the answers i need to get different then the ones yall are giving
bro how do you get that
To determine two pairs of polar coordinates for the point (3, -3), we can use the following formula:
r = √(x^2 + y^2)
θ = arctan(y/x)
Given that the point is (3, -3), we can substitute these values into the formula to find the corresponding polar coordinates.
First, let's calculate r:
r = √(3^2 + (-3)^2)
= √(9 + 9)
= √18
≈ 4.24264
Now, let's calculate θ:
Since x = 3 and y = -3, we can find θ by using the inverse tangent function:
θ = arctan((-3)/3)
≈ arctan(-1)
≈ -45°
We have the first pair of polar coordinates: (r, θ) = (4.24264, -45°).
To find the second pair of coordinates, we add 180° to the angle:
θ2 = -45° + 180°
= 135°
Therefore, the second pair of polar coordinates is: (r, θ2) = (4.24264, 135°).
Hence, the two pairs of polar coordinates for the point (3, -3) are (4.24264, -45°) and (4.24264, 135°).