solve the linear equation: 3X2y-7=19,4y-y+27=4y-52=32.?
Ditto what Steve said in your last post
I apologize, but there seems to be an error in the way you have written the equations. Please double-check and provide the correct equations so that I can assist you in solving them step-by-step.
To solve the linear equations, let's start with the first equation:
3x - 2y - 7 = 19
To isolate the variable terms, we will move the constant term (-7) to the other side of the equation by adding 7 to both sides:
3x - 2y = 19 + 7
3x - 2y = 26
Now, let's move to the second equation:
4y - y + 27 = 4y - 52
To isolate the variable terms, we will simplify the equation first:
3y + 27 = 4y - 52
Next, we will move the variable terms to one side and the constant terms to the other side:
3y - 4y = - 52 - 27
-y = - 79
To solve for y, we can multiply both sides by -1 to get rid of the negative sign:
y = 79
Now that we have the value for y, we can substitute it back into the first equation to solve for x:
3x - 2(79) = 26
3x - 158 = 26
To isolate the variable term, we will move the constant term (-158) to the other side by adding 158 to both sides:
3x = 26 + 158
3x = 184
Finally, we divide both sides by 3 to solve for x:
x = 184 / 3
Therefore, the solution to the equations is x ≈ 61.3333 and y = 79.