Factor the trinomial:
2x^2 +11x - 63
factors of 2 are 1,2
factors of 63 are 9,7 ; 21,3
after a couple tries I got
(x + 9)(2x - 7)
To factor the trinomial 2x^2 + 11x - 63, you can use the following steps:
Step 1: Check for a common factor
In this case, there is no common factor among the coefficients, so we move to the next step.
Step 2: Multiply the coefficient of the quadratic term (2) by the constant term (-63)
2 * (-63) = -126
Step 3: Look for factors of the result from step 2 (-126) that add up to the coefficient of the linear term (11).
Factors of -126 that add up to 11 are -7 and 18.
Step 4: Rewrite the original trinomial by splitting the linear term (11x) using the factors found in step 3.
2x^2 - 7x + 18x - 63
Step 5: Group the terms and factor by grouping.
(2x^2 - 7x) + (18x - 63)
x(2x - 7) + 9(2x - 7)
Step 6: Factor out the common binomial factor.
(2x - 7)(x + 9)
Therefore, the factored form of the trinomial 2x^2 + 11x - 63 is (2x - 7)(x + 9).