a company was charged $290 for 13 frames. it was charged $430 for 20 frames.
A. use the coordinates (13,290) and (20,430) to write a linear equation in point slope form that gives the relationship of the cost to the number of frames
B. find the cost for 25 frames.
You have posted 5 questions that are done the same way. I will do this one, and you do the previous 4
slope between the two points (13,290) and (20,430)
= (430-290)/(20-13) = 140/7 = 20
equation:
y-290 = 20(x-13)
arrange it in any way you want.
e.g.
y = 20x - 260 + 290
y = 20x + 30 would be the slope-yintercept form
What is the answer for B
To write a linear equation in point-slope form, we can use the formula:
y - y1 = m(x - x1)
where (x1, y1) are the coordinates of a point on the line, and m is the slope of the line.
Given the coordinates (13, 290) and (20, 430), we can find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the coordinates (13, 290) and (20, 430), we have:
m = (430 - 290) / (20 - 13)
m = 140 / 7
m = 20
So, the slope (m) of the line is 20.
Now, let's choose one of the points to substitute into the point-slope form equation. Let's use (13, 290).
Using the formula, we have:
y - 290 = 20(x - 13)
Simplifying, we get:
y - 290 = 20x - 260
Adding 290 to both sides:
y = 20x - 260 + 290
y = 20x + 30
Therefore, the linear equation in point-slope form that represents the relationship between the cost and the number of frames is y = 20x + 30.
To find the cost for 25 frames, we can substitute x = 25 into the equation and solve for y.
y = 20x + 30
y = 20(25) + 30
y = 500 + 30
y = 530
So, the cost for 25 frames would be $530.