subtractand simplify 7-x/x-9-7x-8/9-x.
I got (6x-1)/(x-9)
Is this correct?
The way you typed it, I see 6 terms, and I would guess that is not what you meant
Is it (7-x)/(x-9) - (7x-8)/(9-x) ?
or ... ( many ways it could be written)
I am saying: You will need brackets to tell us the order of operation
Yes that is the order
To subtract and simplify the expression (7 - x) / (x - 9) - (7x - 8) / (9 - x), we need to find a common denominator and then combine the fractions.
First, let's find the common denominator for the two fractions. The denominators are (x - 9) and (9 - x). Notice that (9 - x) is the negation of (x - 9), so we can rewrite it as -(x - 9).
The common denominator for the two fractions is then (x - 9) * (-(x - 9)), which simplifies to (x - 9) * (9 - x).
Now, let's rewrite each fraction with the common denominator:
(7 - x) / (x - 9) = (7 - x) * (9 - x) / [(x - 9) * (9 - x)]
(7x - 8) / (9 - x) = (7x - 8) * (x - 9) / [(x - 9) * (9 - x)]
Next, we can combine the fractions:
[(7 - x) * (9 - x) - (7x - 8) * (x - 9)] / [(x - 9) * (9 - x)]
Expanding the numerator, we get:
[63 - 7x - 9x + x^2 - 7x^2 + 63x - 72 - 8x + 72] / [(x - 9) * (9 - x)]
Combining like terms, we have:
[-6x^2 + 47x + 63] / [(x - 9) * (9 - x)]
So, the simplified expression is (-6x^2 + 47x + 63) / [(x - 9) * (x - 9)].
Therefore, your answer of (6x - 1) / (x - 9) is not correct.