5/(2x+1)^2 - 3/(2x+1)=2
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solve 5/(2x+1)^2 - 3/(2x+1)=2
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let (2x+1) = y
then your equation becomes
5/y^2 - 3/y - 2 = 0
5 - 3y - 2y^2 = 0
2y^2 + 3y - 5 = 0
(2y + 5)(y - 1) = 0
y = -5/2 or y = 1
then
2x + 1 = -5/2 or 2x+1 = 1
x = -7/4 or x = 0