Suppose that the number of insects captured in a trap on

different nights is normally distributed with mean 2950 and standard deviation 550.
a) What is the probability of capturing between 2500 and 3500 insects?
b) Suppose that we change the location of a trap whenever it captures a
number of insects that fall in the lowest 5%. If a trap was relocated on a
given night, what is the maximum number of insects that it captured?
c) What is the probability of capturing between 2600 and 2850 insects?
d) Suppose that we call an exterminator whenever a trap captures a number of insects that fall in the highest 10%. If an exterminator was called on a given night, what is the minimum number of insects that the trap captured?

the size of chicken eggs is usually given in ounces per dozen. there are 6size: 15,18,21,24,27,and 30 ounces per dozen.

Which statistic best describes the size of a chicken egg? Explain

http://psych.colorado.edu/~mcclella/java/normal/accurateNormal.html

The size of chicken eggs is usually given in ounces per dozen. There are 6 size: 15,18,21,24,27,and 30 ounces per dozen.

Which statistic best describes the size of a chicken egg? Explain.

Explain Bot Explain Bot answered
9 months ago

To answer the questions about the insects captured in a trap, we need to use the properties of a normal distribution.

a) To find the probability of capturing between 2500 and 3500 insects, we need to calculate the z-scores for these values and then use a z-table or a statistical calculator.

The z-score formula is: z = (x - μ) / σ
where x is the value, μ is the mean, and σ is the standard deviation.

For 2500 insects: z = (2500 - 2950) / 550 = -0.818
For 3500 insects: z = (3500 - 2950) / 550 = 1

Using a z-table or a statistical calculator, we can find the area (probability) between these two z-scores. The probability of capturing between 2500 and 3500 insects is the difference between these two probabilities.

b) To find the maximum number of insects that would trigger a trap relocation on a given night (lowest 5%), we need to find the z-score corresponding to the lowest 5% of the distribution.

Using a z-table or a statistical calculator, we can find the z-score that corresponds to the cumulative probability of 5%. Once we have the z-score, we can use the formula to find the maximum number of insects:

Max insects = (z * σ) + μ

c) To find the probability of capturing between 2600 and 2850 insects, we follow the same steps as in part a. Calculate the z-scores for these values and find the area between the z-scores using a z-table or a statistical calculator.

d) To find the minimum number of insects that would trigger calling an exterminator on a given night (highest 10%), we need to find the z-score corresponding to the highest 10% of the distribution.

Using a z-table or a statistical calculator, we can find the z-score that corresponds to the cumulative probability of 90%. Once we have the z-score, we can use the formula to find the minimum number of insects:

Min insects = (z * σ) + μ

Regarding the statistic that best describes the size of a chicken egg, the mean (μ) would be the most appropriate statistic. The mean represents the average size of the eggs in the given set of six sizes (15, 18, 21, 24, 27 and 30 ounces per dozen). It provides a measure of central tendency, giving us a representative value for the size of chicken eggs.