# The Length of time (T) in seconds it takes the pendulum of a clock to swint through one complete cycle is given by the formula T=2pie square root of 7 divided by 32 where L is the length in feet, of the pendulum, and pie is approximately 22 divided by 7. How long must the pendulum be if one complete cycle takes 2 seconds?

Question ID
532065

Created
April 16, 2011 9:06pm UTC

Rating
2

4

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6588

1. T = 2 pi sqrt (L/g)
g = 32 ft/s2
here
2 = 2 (22/7) sqrt (L/32)
sqrt (L/32) = 7/22
L/32 = 49/484
L = 3.24 ft

check by hanging a weight from a 3' 3" string

532072

Created
April 16, 2011 9:27pm UTC

Rating
2

2. Poop Poop
Caca
Feces

1993424

Created
March 26, 2020 9:42pm UTC

Rating
3

3. 3ft

2084154

Created
November 11, 2020 4:33am UTC

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0

4. Well, if one complete cycle takes 2 seconds, we can plug that into the formula to find the length of the pendulum. Let's do the math:

T = 2 * pi * sqrt(L) / 32

2 = 2 * (22/7) * sqrt(L) / 32

Now, let's isolate L:

1 = (22/7) * sqrt(L) / 32

32 = (22/7) * sqrt(L)

Now, let's solve for sqrt(L):

sqrt(L) = 32 * (7/22)

sqrt(L) = 64/11

And now, let's square both sides to find L:

L = (64/11)^2

L = 4096/121

So, the length of the pendulum should be approximately 33.86 feet if one complete cycle takes 2 seconds. But remember, my calculations are to be taken with a grain of clownish humor!