T= k sqrt L
15 = k sqrt 9 = k * 3
k = 5
so
T = 5 sqrt L
80 = 5 sqrt L
16 = sqrt L
L = 16^2 = 256 cm
15 = k sqrt 9 = k * 3
k = 5
so
T = 5 sqrt L
80 = 5 sqrt L
16 = sqrt L
L = 16^2 = 256 cm
We have the length of a pendulum that beats 15 seconds as 9 centimeters. Now, we need to find the length that beats 80 seconds.
To solve this, let's use the formula:
(length1 / time1) = (length2 / time2)
Plugging in the values we know, we have:
(9 / 15) = (length2 / 80)
Now, we can cross-multiply and solve for length2:
(9 * 80) = (15 * length2)
720 = 15 * length2
Dividing both sides by 15, we get:
length2 = 720 / 15
length2 = 48 centimeters
So, the length of the pendulum that beats 80 seconds would be 48 centimeters. Just be careful not to trip over that long pendulum!
Let's first establish the direct variation equation:
time โ โ(length)
Given that a pendulum with a length of 9 centimeters beats for 15 seconds, we can write the equation as:
15 โ โ9
Now, solve for the constant of proportionality by squaring both sides of the equation:
225 = 9
We can rewrite the equation as:
225 = k * 9
Divide both sides of the equation by 9 to isolate the constant:
25 = k
Now that we have found the constant of proportionality (k = 25), we can find the length of the pendulum that beats for 80 seconds:
time โ โlength
80 โ โlength
Solve for the length by squaring both sides of the equation again:
6400 = length
Therefore, the length of the pendulum that beats for 80 seconds is 6400 centimeters.