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a shaft rotation @ 800 rpm delivers a torque of 240 N.m to an output shaft that is rotating @ 200 rpm.

a. if the efficiency of the machine is 70%, compute the output torque
b, what is the output power

e=Po/Pi .7=x/240 N.m = 168 N.m

this is not the answer in the book so I obviously have no idea what I am doing...help?

Question ID
524980

Created
April 4, 2011 12:35am UTC

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https://questions.llc/questions/524980

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  1. .7=Torque*200/240*600

    torque out=.7*3*240

    Answer ID
    525037

    Created
    April 4, 2011 1:35am UTC

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