A type of elevator called a cage is used to raise and lower miners in a mine shaft. Suppose the cage carries a group of miners down the shaft. If the unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is 1.50 × 10 2kg, what is the acceleration of the cage?
a = F/m = 60 / 150 = 6/15 = 2/5 = 0.40 m/s^2
almost half a g, wow !
Gavin wants a cage for his new gerbil, Gary. He found that Gary was 4 3/4 inches from his the tip of his nose to the tip of his tail. Gavin's mom said they would get a larger cage when Gary reached 6 inches. How many more inches does Gary need to grow before Gavin needs to buy a new cage?
To find the acceleration of the cage, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Unbalanced force (F) = 60.0 N
Mass of the loaded cage (m) = 1.50 × 10^2 kg
Using Newton's second law:
F = m * a
Rearranging the equation to solve for acceleration (a), we have:
a = F / m
Substituting the given values, we get:
a = 60.0 N / (1.50 × 10^2 kg)
Calculating the acceleration:
a = 0.4 m/s^2
Therefore, the acceleration of the cage is 0.4 m/s^2.
To find the acceleration of the cage, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula for Newton's second law is:
F = m * a
Where:
F = net force
m = mass of the object
a = acceleration
In this case, the unbalanced force on the cage is given as 60.0 N, and the mass of the loaded cage is 1.50 × 10^2 kg. Plugging these values into the formula, we get:
60.0 N = (1.50 × 10^2 kg) * a
Now, let's solve for 'a':
a = 60.0 N / (1.50 × 10^2 kg)
a ≈ 0.4 m/s^2
Therefore, the acceleration of the cage is approximately 0.4 m/s^2.