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A mixture of aluminum and zinc metal is used in 2 experiments described below:

A- A 1.7 gram sample of the mixture is reacted with excess hydrochloric acid and the resulting hydrogen gas is collected over water. The reaction takes place at 750 mm Hg atmospheric pressure and 25C. VP of water = 23.8 torr.

B- In a separate experiment, 1.4 grams of the mixture is reacted with a stoichiometric quantity of hydrochloric acid. The resulting solution is treated with a concentrated ammonia solution. A precipitate forms that is collected and dried. The mass of the precipitate is 2.70 gms.

Calculate the volume of the hydrogen gas collected in A.

Any help would be appreciated, even if it is just where to start.
Im mainly confused on how you know what amount of aluminum or zinc is in the samples of the mixture

AP Chemistry - DrBob222, Sunday, April 3, 2011 at 2:49pm
You find that from part B. The reaction in part B is
Zn + 2HCl ==> ZnCl2 + H2
2Al + 6HCl ==> 2AlCl3 + 3H2

At this point you have Zn^+2 ions and Al^+3 ions in solution. Treatment with concd NH3 solution forms Al(OH)3 with the aluminum ions and Zn(NH3)4^+2 with the zinc ions. So convert 2.70 g of the ppt formed [Al(OH)3] to grams Al and subtract from the total to arrive at the grams Zn. I would get a percent at this point. Then go back to part A, use the percentage to find the amount Zn and Al in the 1.7 g sample, then through the stoichiometry to find the moles H2 from Zn and moles H2 from Al, then use PV = nRT to solve for volume in liters.

AP Chemistry - Kate, Sunday, April 3, 2011 at 3:41pm
Where does the Al(OH)3 come from and how do you know and how do you tell how much of the 2.70g of ppt is Al(OH)3 or Zn(NH3)4^+2??


Question ID

April 3, 2011 8:43pm UTC





1 answer

  1. I just finished answering your follow up question below. See the original post.

    Answer ID

    April 3, 2011 8:49pm UTC



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