Find the x coordinates of all relative extreme points of
f(x)=1/4x^4 + 2/3x^3- 3/2x^2 + 4
f'(x)=x^3 + 2x^2 - 3x = 0
(x^2 + 3)(x-1) = 0
x=-3 x=1 x=0 Is this correct?
f(x)=1/4x^4 + 2/3x^3- 3/2x^2 + 4
f'(x)=x^3 + 2x^2 - 3x = 0
(x^2 + 3)(x-1) = 0
x=-3 x=1 x=0 Is this correct?