Question

P and Q are points of trisection of a line segment joining points A(-8,12) and B (1,-3). P is nearer to A. Find the coordinates of P. Please answer ASAP!!

Answer 1

P is 1/3 of the way from A to B.

The difference in coordinates when moving from A to B is (9,-15)
So, P = A+(3,-5) = (-8,12)+(3,-5) = (-5,7)
and Q = (-5,9) + (3,-5) = (-2,4)
Finally, adding another (3,-5) gets you to (1,-3) = B

If P is 1/n of the way from A to B, P = A + 1/n (B-A)

Answer 2

Ver bad

Answer 3

[AI-generated answer — Step-by-Step Bot]

To find the coordinates of point P, we need to calculate the coordinates using the concept of trisection.

Step 1: Calculate the differences in x and y coordinates between points A and B.
Δx = Bx - Ax = 1 - (-8) = 9
Δy = By - Ay = -3 - 12 = -15

Step 2: Divide the differences by 3 to find the increments.
increment_x = Δx / 3 = 9 / 3 = 3
increment_y = Δy / 3 = -15 / 3 = -5

Step 3: Add the increments to the coordinates of point A to find the coordinates of point P.
Px = Ax + increment_x = -8 + 3 = -5
Py = Ay + increment_y = 12 + (-5) = 7

Therefore, the coordinates of point P are (-5, 7).

Answer 4

[AI-generated answer — Explain Bot]

To find the coordinates of point P, we need to find the coordinates that are two-thirds of the way from point A to point B.

First, we find the differences in x-coordinates and y-coordinates between points A and B:
Δx = Bx - Ax = 1 - (-8) = 9
Δy = By - Ay = -3 - 12 = -15

Next, we determine the increment for each coordinate by dividing Δx and Δy by 3:
Increment_x = Δx / 3 = 9 / 3 = 3
Increment_y = Δy / 3 = -15 / 3 = -5

Starting from point A, we apply the increments to find point P:
Px = Ax + Increment_x = -8 + 3 = -5
Py = Ay + Increment_y = 12 - 5 = 7

Therefore, the coordinates of point P are (-5, 7).