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During the first part of a trip a canoeist travels 93 miles at a certain speed. The conoiest travels 5 miles on the second trip at 5mph slower. The total time for the trip is 2 hrs. What was the speed on each part of the trip?

I entered 1.999 as answer given, but it was wrong. Thank you so very much for all your help.

Thank you for all your help.

Question ID
523822

Created
April 1, 2011 5:54am UTC

Rating
0

URL
https://questions.llc/questions/523822

Answers
2

Views
357

2 answers

  1. So the first thing I wonder about is significant digits, you may not know about that,but your answer to four places when one (5 miles) is given is a stretch in the real world.

    he went 98miles in 2 hours.

    93=certainspeed*time1
    5=(certainspeed-5)(2-time1)

    so solve for time1 in the first equation, put it in the second.

    time1=93/certainspeed

    5=(certainspeed-5)(2-93/certain speed)

    multiply both sides by certain speed S

    5S=(S-5)(2S-93)

    multiply out the right side, collect terms,you have a quadratic, which can be solved for certain speed S.

    Answer ID
    523830

    Created
    April 1, 2011 7:54am UTC

    Rating
    0

    URL

  2. Ester, if you entered 1.999, then you did not enter the answer that I worked out for you.
    I had the two rates as 49.3 mph and 44.3 mph which I had verified as being correct.

    http://www.jiskha.com/display.cgi?id=1301620679

    Answer ID
    523852

    Created
    April 1, 2011 12:17pm UTC

    Rating
    0

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