How many grams of NaCl are required to make up 2.00 L of a 4.00 M solution of NaCl
How many moles do you want? moles = M x L.
How many grams do you need?
moles = grams/molar mass. Solve for grams.
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To find out how many grams of NaCl are required to make a 4.00 M solution in 2.00 L, we need to use the formula:
moles = concentration (M) × volume (L)
First, let's convert the volume from liters to milliliters since the unit of concentration is in moles per liter.
2.00 L = 2000 mL
Now we can calculate the moles of NaCl needed:
moles = 4.00 M × 2000 mL
To convert milliliters to liters, divide by 1000:
moles = 4.00 M × 2.00 L
moles = 8.00 mol
Next, we need to convert moles to grams using the molar mass of NaCl, which is 58.44 g/mol.
grams = moles × molar mass
grams = 8.00 mol × 58.44 g/mol
grams = 467.52 g
Therefore, you would need 467.52 grams of NaCl to make a 4.00 M solution in 2.00 L.