how many grams of nacl are required to completely neutralize of 1 M of h2so4
write the balanced equation
see how many moles of NaCl are required for each mole of H2SO4
convert that to grams of NaCl
To determine the number of grams of NaCl required to completely neutralize 1 M of H2SO4, we need to use stoichiometry.
The balanced chemical equation for the neutralization reaction between NaCl and H2SO4 is:
2 NaCl + H2SO4 -> 2 HCl + Na2SO4
From the equation, we can see that 2 moles of NaCl react with 1 mole of H2SO4.
To find the number of grams of NaCl required, we need to consider the molar mass of NaCl. It is composed of one sodium (Na) atom with a molar mass of 22.99 g/mol and one chlorine (Cl) atom with a molar mass of 35.45 g/mol. Adding these together, we get a molar mass of NaCl as 58.44 g/mol.
Now, let's calculate the number of moles of H2SO4 present in 1 M solution. The "M" in 1 M represents 1 mole of H2SO4 dissolved in 1 liter of solution. Therefore, we have 1 mole of H2SO4 in 1 liter.
Finally, to find the number of grams of NaCl needed to neutralize this, we can set up a proportion:
(2 moles NaCl / 1 mole H2SO4) = (x grams NaCl / 1 mole NaCl)
Where x represents the grams of NaCl we need.
By cross-multiplying and solving the equation, we find:
2 moles NaCl = x grams NaCl
So, 2 moles NaCl is equal to x grams NaCl.
Therefore, to completely neutralize 1 M of H2SO4, we would need 2 moles or 116.88 grams of NaCl.