a 0.100m k2so4 solution has a freezing point of -0.43 degrees. what is the van hoff factors for this solution? kf=1.86degree/m?
0.77
3.0
1.0
2.3
i have used the equation dT=iKfm and get -2.3?
-.43=k*-1.86*.1
solve for k. Where did you minus sign come from?
I only have -0.46 degrees, not -1.86 so it stays a -ve, i guess.
that is an assignment question word for word.
is Kf meant to be -ve?
eee -w-
To find the van't Hoff factor (i) for a solution, you need to use the equation you mentioned, dT = iKfΔm, where dT is the change in freezing point, Kf is the cryoscopic constant, and Δm is the molality of the solution.
Given:
- Kf = 1.86 °C/m (cryoscopic constant)
- ΔT = -0.43 °C (change in freezing point)
- m = 0.100 mol/kg (molality of the solution)
Substituting the given values into the equation, we can solve for i:
-0.43 °C = i * 1.86 °C/m * 0.100 mol/kg
Simplifying the equation further:
-0.43 = 0.186 i
Now, solve for i:
i = -0.43 / 0.186
By dividing these two numbers, we get:
i ≈ -2.3
However, the van't Hoff factor (i) should always be a positive whole number. Since it cannot be negative, you made a mistake in your calculations. The van't Hoff factor must be a positive integer value.
Considering the available answer choices, the closest positive integer value to -2.3 is 2. Therefore, the correct van't Hoff factor for this solution is likely 2.