1500 * 0.05 = 75
75g of K2SO4 to make 1500g of a 5% solution.
75g of K2SO4 to make 1500g of a 5% solution.
First, we need to find out how much K2SO4 is actually in the solution. Since it's a 5.0% solution, that means 5% of the 1500 g will be K2SO4. So, 5% of 1500 g is 75 g.
This means you'll need 75 grams of K2SO4 to prepare your 1500 g of 5.0% K2SO4 solution. Who knew math could be so salty?
The term "5.0% (m/m)" means that the mass of K2SO4 is 5.0% of the total mass of the solution.
Step 1: Calculate the mass of K2SO4 in the solution.
Total mass of the solution = 1500 g
Mass percent of K2SO4 = 5% = 5/100 = 0.05
Mass of K2SO4 = (Mass percent of K2SO4) x (Total mass of the solution)
= 0.05 x 1500 g
= 75 g
Therefore, you would need 75 grams of K2SO4 to prepare 1500 g of a 5.0% K2SO4 (m/m) solution.
% m/m = (mass of solute / mass of solution) × 100
In this case, we know the mass of the solution is 1500 g and the desired percentage of K2SO4 is 5.0% (m/m).
Step 1: Calculate the mass of K2SO4 in the solution.
% m/m = (mass of K2SO4 / mass of solution) × 100
Rearranging the equation, we get:
mass of K2SO4 = (mass of solution × % m/m) / 100
Substituting the values:
mass of K2SO4 = (1500 g × 5.0%) / 100
Step 2: Calculate the mass of K2SO4.
mass of K2SO4 = (1500 g × 5.0) / 100
mass of K2SO4 = 75 g
Therefore, you would need 75 grams of K2SO4 to prepare 1500 grams of a 5.0% (m/m) K2SO4 solution.