# I have a hard time solving this problem.

The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?

wouldn't one multiply by 320(proportional to mass) and divide by 11 squared (inversely proportional to the square of distance)?

2.6N

16 years ago

16 years ago

16 years ago

16 years ago

13 years ago

13 years ago

7 months ago

## To solve this problem, you are on the right track with considering the proportional relationship to mass and the inverse square relationship with the radius. Here's how you can find the weight of the apple on Jupiter:

1. Identify the given information:
- Earth's radius (rE) = 1 (unit)
- Jupiter's radius (rJ) = 11rE
- Earth's mass (mE) = 1 (unit)
- Jupiter's mass (mJ) = 320mE
- Weight of the apple on Earth = 1.0 N

2. Use the proportional relationship with mass:
Since Jupiter's mass is 320 times greater than Earth's, you can multiply the weight of the apple on Earth by 320 to find the weight of the apple on Jupiter if the radius is the same. This gives you 320 x 1.0 N = 320 N.

3. Use the inverse square relationship with the radius:
Since the weight is inversely proportional to the square of the radius, you need to divide the weight by the square of the radius ratio. The radius ratio is (rJ/rE)Â² = (11/1)Â² = 121.
Therefore, you need to divide the weight of the apple on Jupiter (320 N) by 121: 320 N Ã· 121 = 2.64 N.

So, the weight of the apple on Jupiter would be approximately 2.64 N, not 2.6 N.

🤔 🤔 Ask a New Question 🤔 🤔