Poll of statistic students revealed that 44% study alone, 31% study in a group, 12% study both alone and in a group
Find the probability that a randomly selected statistic student studies alone but not in a group.
I made a Venn diagram, showing 12% in the intersection of the "alone" circle and the "group" circle.
It showed 32% falling in the "alone" only part, and 19% falling in the "group" only part.
This left 63% outside the two circles.
Does that mean that 63% don't study at all? Or they study in some other way?
Anyway the probability that they study alone and not in a group is .32
That was one of the answers it was a multiple choice question so I think you are right too Thanks
To find the probability that a randomly selected statistics student studies alone but not in a group, we need to subtract the percentage of students who study both alone and in a group from the percentage of students who study alone.
1. First, calculate the percentage of students who study alone but not in a group.
- Percentage of students who study alone = 44%
- Percentage of students who study both alone and in a group = 12%
- Percentage of students who study alone but not in a group = Percentage of students who study alone - Percentage of students who study both alone and in a group
= 44% - 12%
= 32%
2. Convert the percentage to probability.
- Probability = Percentage / 100
= 32% / 100
= 0.32
Therefore, the probability that a randomly selected statistics student studies alone but not in a group is 0.32 or 32%.