A line has a slope m=1/3 and it passes through the point (3, 4). Find the equation for the line in slope-intercept form.
a.)y = 1/3x + 3
b.)y - 4 = 1/3(x - 3)
c.)y - 3 = 1/3(x - 4)
I figured out the answer by using the slope intercept formula:
y-y1=m(x-x1)
y - 4 = 1/3(x - 3)
the slope intercept form has the appearance of
y = mx+b
so you will have to continue with your correct starting equation
y - 4 = 1/3(x - 3)
y - 4 = (1/3)x - 1
y = (1/3)x - 1 + 4
y = (1/3)x + 3 , which is choice a)
Thanks:)
To find the equation of a line in slope-intercept form (y = mx + b), you need two pieces of information: the slope (m) and a point (x, y) that the line passes through.
Given that the slope (m) of the line is 1/3 and it passes through the point (3, 4), we can substitute these values into the slope-intercept form and find the equation.
Using the point-slope form of a line, which is (y - y1) = m(x - x1), where (x1, y1) is the given point, we can substitute the values (x1 = 3, y1 = 4) and the slope (m = 1/3).
So, using the point-slope form, we have:
(y - 4) = 1/3(x - 3)
To convert this to the slope-intercept form (y = mx + b), we can rearrange the equation by isolating y:
y - 4 = 1/3x - 1
y = 1/3x - 1 + 4
y = 1/3x + 3
Comparing this equation with the options given, we see that the correct answer is:
a.) y = 1/3x + 3