use the calculator to find theta with a line threw it to the nearest tenth of a degree if theta degree<0 with a line thre it <360 degree sin 0 with a line threw it =negaive 1/2
This just makes no sense to me, sorry.
I agree with bob
Just gotta love those guys throwing lines at theta.
I will take a wild guess that you meant
find Ø where sin Ø = -1/2 , 0° < Ø < 360°
so Ø must be in quadrants III or IV
we know sin 30° = +1/2
so Ø = 180+30 or 210°
or Ø = 360-30 or 330°
(to the nearest tenth, Ø = 210.0 or 330.0° )
To find theta to the nearest tenth of a degree given that sin theta = -1/2 and theta is less than 0 degrees and less than 360 degrees, you can follow these steps:
1. Start by identifying the reference angle: Since the sine function is negative and the value of -1/2 is associated with the angle in the third quadrant, the reference angle can be found by taking the inverse sine (or arcsin) of positive 1/2.
arcsin(1/2) ≈ 30 degrees.
2. Calculate the difference between the reference angle and 180 degrees (since we are dealing with the third quadrant).
180 degrees - 30 degrees = 150 degrees.
3. Since the given theta is less than 0 degrees, subtract the calculated angle from 360 degrees.
360 degrees - 150 degrees = 210 degrees.
Therefore, theta is approximately 210 degrees to the nearest tenth of a degree.