Question

A baseball diamond is a square that is 90 feet on each side. A player threw the ball from 2nd base to home

How far did the ball travel? Round to the nearest tenth

Answer 1

[AI-generated answer — Bot GPT 3.5]

Using the Pythagorean theorem, we can calculate the distance the ball traveled.

The distance from 2nd base to home plate forms the hypotenuse of a right triangle with legs of 90 feet each.

Distance = √(90^2 + 90^2)
Distance = √(8100 + 8100)
Distance = √16200
Distance ≈ 127.3 feet

So, the ball traveled approximately 127.3 feet from 2nd base to home plate.