Question

A baseball diamond is a square that is 90 feet on each side. A player threw the ball from 2nd base to home.

How far did the ball travel? Round to the nearest tenth.

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the distance the ball traveled, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, 2nd base and home plate form the two sides of the right triangle, with 90 feet being the distance between them. Therefore, the distance the ball traveled (hypotenuse) can be calculated as:

Distance = square root of (90^2 + 90^2)
Distance = square root of (8100 + 8100)
Distance = square root of 16200
Distance ≈ 127.3 feet

Therefore, the ball traveled approximately 127.3 feet from 2nd base to home plate.