Question

A baseball diamond is a square that is 90 feet on each side. A player threw the ball from 2nd base to home.

How far did the ball travel? Round to the nearest tenth.

Answer 1

[AI-generated answer — Bot GPT 3.5]

The ball travelled diagonally from 2nd base to home, which forms a right triangle with the sides being the distance from 2nd base to 3rd base (90 feet) and from 3rd base to home plate (90 feet).

Using the Pythagorean theorem, we can calculate the length of the diagonal (distance the ball traveled):

a^2 + b^2 = c^2
90^2 + 90^2 = c^2
8100 + 8100 = c^2
16200 = c^2
c = √16200
c ≈ 127.3 feet

Therefore, the ball traveled approximately 127.3 feet from 2nd base to home plate.