Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
x^2 + 3 = -4x
A: 1, 3
B: -1, -3
C: 1, -3
D: -1, 3
To solve the equation x^2 + 3 = -4x, we first need to rewrite it in standard form, which is x^2 + 4x + 3 = 0.
Now we can use the quadratic formula, which is x = (-b ± √(b^2 - 4ac)) / 2a.
In this equation, a = 1, b = 4, and c = 3.
Plugging these values into the quadratic formula, we get:
x = (-4 ± √(4^2 - 4*1*3)) / 2*1
x = (-4 ± √(16 - 12)) / 2
x = (-4 ± √4) / 2
x = (-4 ± 2) / 2
This gives us two possible values for x:
x1 = (-4 + 2) / 2 = -2 / 2 = -1
x2 = (-4 - 2) / 2 = -6 / 2 = -3
Therefore, the solutions to the equation x^2 + 3 = -4x are x = -1 and x = -3.
The answer is B: -1, -3.