Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. x^2-21=-4x

We rewrite the equation in standard form: x^2 + 4x - 21 = 0.

We can now use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 1, b = 4, and c = -21.

Substituting these values, we get:

x = (-4 ± √(4^2 - 4(1)(-21))) / 2(1)

x = (-4 ± √(16 + 84)) / 2

x = (-4 ± √100) / 2

We simplify the square root:

x = (-4 ± 10) / 2

There are two solutions:

x = (-4 + 10) / 2 = 3

x = (-4 - 10) / 2 = -7

Therefore, the solutions are x = 3 and x = -7.

To solve the quadratic equation x^2 - 21 = -4x using the quadratic formula, we first need to rewrite the equation in the standard form ax^2 + bx + c = 0.

In this case, we have x^2 + 4x - 21 = 0. Comparing this with the standard form, we find that a = 1, b = 4, and c = -21.

Now, let's substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values, we get:

x = (-4 ± √(4^2 - 4(1)(-21))) / (2(1))

Simplifying further, we have:

x = (-4 ± √(16 + 84)) / 2

x = (-4 ± √100) / 2

The square root of 100 is 10, so we have:

x = (-4 ± 10) / 2

Now, we will find the two possible solutions by separately solving for x when taking the positive and negative square roots:

1. For the positive square root:

x = (-4 + 10) / 2

x = 6 / 2

x = 3

2. For the negative square root:

x = (-4 - 10) / 2

x = -14 / 2

x = -7

Therefore, the solutions to the equation x^2 - 21 = -4x are x = 3 and x = -7.

To solve the quadratic equation x^2 - 21 = -4x using the quadratic formula, we first need to rearrange the equation so that it is in the general form ax^2 + bx + c = 0.

Rearrange the equation:
x^2 + 4x - 21 = 0

Now, we can identify the values of a, b, and c:
a = 1
b = 4
c = -21

The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values of a, b, and c into the formula:
x = (-(4) ± √((4)^2 - 4(1)(-21))) / (2(1))

Simplifying further:
x = (-4 ± √(16 + 84)) / 2
x = (-4 ± √(100)) / 2
x = (-4 ± 10) / 2

Now we have two possible solutions:
x1 = (-4 + 10) / 2 = 6 / 2 = 3
x2 = (-4 - 10) / 2 = -14 / 2 = -7

Therefore, the solutions to the equation x^2 - 21 = -4x, rounded to the nearest hundredth, are x = 3 and x = -7.