Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup and fill cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup and fill cans at rate of 12 per minute right equation to show when the two machines will have filled the same number of cans of soup use X as your variable.
Let x be the number of minutes it takes for the two machines to have filled the same number of cans of soup.
Machine 1 can fill cans at a rate of 15 cans per minute, so the total number of cans filled by Machine 1 can be expressed as:
15x + 180
Machine 2 can fill cans at a rate of 12 cans per minute, so the total number of cans filled by Machine 2 can be expressed as:
12x + 210
Setting the two expressions equal to each other gives us the equation:
15x + 180 = 12x + 210
Subtracting 12x from both sides gives:
3x + 180 = 210
Subtracting 180 from both sides gives:
3x = 30
Dividing by 3 gives:
x = 10
Therefore, the two machines will have filled the same number of cans of soup in 10 minutes.