Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)

Question

Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)

Responses

12x+210=15x+180
12 x plus 210 equals 15 x plus 180

210−12x=180−15x
210 minus 12 x equals 180 minus 15 x

12x+180=15x+210
12 x plus 180 equals 15 x plus 210

12x−210=15x−180

Answer 1

The correct equation to show when the two machines will have filled the same number of cans of soup is:

12x + 210 = 15x + 180

where x is the number of minutes it will take for the two machines to fill the same number of cans of soup.

Answer 2

Movie theatre A has a popcorn machine with a 100-gallon capacity and sells 3 gallons of popcorn per hour. Move theatre B has a popcorn machine with a 150 gallon capacity and sells 5 gallon of popcorn per hour. Write an equation to show when the two popcorn machines will have the same amount of popcorn left. Use x as your variable

Answer 3

12x - 210 = 15x - 180

Answer 4