a boy lifts the load of 50 kg from the ground to a height of 6 m within a time of 10 minutes. Calculate the work done by the boy .(assuming g=10m/s²)
First, we need to calculate the gravitational potential energy (GPE) of the load at a height of 6m.
GPE = mgh
GPE = 50kg * 10m/s² * 6m
GPE = 3000 J
Since the boy is lifting the load at a constant speed, the work done by the boy is equal to the change in gravitational potential energy.
Work = GPE
Work = 3000 J
Therefore, the work done by the boy to lift the load of 50 kg to a height of 6 m in 10 minutes is 3000 Joules.