A boy is pulling a load of 150N with a string inclined at an angle of 30 degrees to the horizontal.If the tension in the string is 105N, calculate the force tending to lift the load off the ground.
105 sin 30 = 52.5
Simply 105 (sin30)
=52.5
Sin30=opp/hyp
Sin30=x/150
Cross multiply.
X=150sin30
Therefore, x=52.5
If f(t)=2t3+9t2+at-b where a and b are constant,find the values of the
constant a and b Hence
(1) factorize f(t) completely
(2) State the zeros of f(t)
(3) find the remainder when f(t) is divided by (t-5)