# A silver-copper alloy had a mass of 0.1264g. When the alloy was dissolved in nitric acid and the silver precipitated as silver chloride, the precipitate had a mass of 0.1375g. Calculate the percent of silver in the alloy. Show your calculations.

## Well, well, looks like we have a chemistry question here! Don't worry, I'm not clowning around when it comes to calculations. Let's get started, shall we?

First, we need to find the mass of silver in the alloy. To do that, we'll subtract the mass of the precipitate (which is silver chloride) from the initial mass of the alloy.

Mass of silver = Mass of alloy - Mass of silver chloride

Mass of silver = 0.1264g - 0.1375g

Mass of silver = -0.0111g

Hold on, that doesn't seem right. Did the mass of silver disappear into thin air? As a clown, I love magic tricks, but we can't have disappearing elements in our calculations. Clearly, we made a mistake somewhere. Let me check my calculations and try again.

Ah, silly me! It seems I made a mistake. I should have subtracted the mass of the alloy from the mass of the precipitate to get the mass of silver. Let's fix this blunder:

Mass of silver = Mass of silver chloride - Mass of alloy

Mass of silver = 0.1375g - 0.1264g

Mass of silver = 0.0111g

Phew! That's more like it. Now we know that the mass of silver in the alloy is 0.0111g.

To find the percentage of silver in the alloy, we'll use the following formula:

% of silver = (Mass of silver / Mass of alloy) × 100

% of silver = (0.0111g / 0.1264g) × 100

% of silver = 8.79%

So, the percent of silver in the alloy is approximately 8.79%. Hope that helps, and sorry for the earlier confusion!

## To calculate the percent of silver in the alloy, we need to determine the amount of silver in the precipitate and compare it to the total mass of the alloy.

1. Calculate the mass of silver in the precipitate:
Mass of precipitate = 0.1375g

2. Calculate the percent of silver in the precipitate:
The molar mass of Ag is 107.87 g/mol, and that of AgCl is 143.32 g/mol. Since one mole of AgCl has one mole of Ag, the mass of silver in the precipitate can be calculated as follows:
Mass of silver = Mass of precipitate / Molar mass of AgCl * Molar mass of Ag
Mass of silver = 0.1375g / 143.32g/mol * 107.87g/mol

3. Calculate the percent of silver in the alloy:
The total mass of the alloy is given as 0.1264g.
Percent of silver = (Mass of silver / Total mass of alloy) * 100

Let's calculate these values step-by-step:

1. Mass of silver in the precipitate:
Mass of silver = 0.1375g / 143.32g/mol * 107.87g/mol
Mass of silver = 0.1036g

2. Percent of silver in the alloy:
Percent of silver = (0.1036g / 0.1264g) * 100
Percent of silver = 81.98%

Therefore, the percent of silver in the alloy is approximately 81.98%.

## To calculate the percent of silver in the alloy, we need to determine the mass of silver and the mass of the alloy.

Step 1: Find the mass of silver precipitated
The mass of the silver chloride (AgCl) precipitate is given as 0.1375g.

Step 2: Calculate the moles of silver chloride
Since silver chloride has a 1:1 mole ratio with silver, the moles of silver chloride are equal to the moles of silver.

Moles = Mass / Molar mass
The molar mass of AgCl = atomic mass of Ag + atomic mass of Cl = 107.87 g/mol + 35.45 g/mol = 143.32 g/mol.

Moles of AgCl = 0.1375 g / 143.32 g/mol

Step 3: Convert moles of AgCl to moles of silver
Since the ratio between silver chloride (AgCl) and silver (Ag) is 1:1, the moles of Ag are the same as the moles of AgCl.

Moles of Ag = Moles of AgCl

Step 4: Calculate the mass of silver
The molar mass of silver (Ag) is 107.87 g/mol.

Mass of silver = Moles of Ag × Molar mass of Ag

Step 5: Find the mass of the alloy
The difference between the initial mass of the alloy and the mass of the silver is equal to the mass of copper present in the alloy.

Mass of alloy = Initial mass - Mass of silver

Step 6: Calculate the percent of silver in the alloy
Percent of silver = (Mass of silver / Mass of alloy) × 100

Now let's substitute the given values and calculate:

Moles of AgCl = 0.1375 g / 143.32 g/mol = 0.0009597 mol

Moles of Ag = Moles of AgCl = 0.0009597 mol

Mass of silver = Moles of Ag × Molar mass of Ag
= 0.0009597 mol × 107.87 g/mol = 0.1036 g

Mass of alloy = Initial mass - Mass of silver
= 0.1264 g - 0.1036 g = 0.0228 g

Percent of silver = (Mass of silver / Mass of alloy) × 100
= (0.1036 g / 0.0228 g) × 100 = 453.5 %

Therefore, the percent of silver in the alloy is 453.5%.

## AgCl had a mass of 0.1375 g. Change that to mols. mols = g/molar mass AgCl.

Convert mols AgCl to mols Ag. That is 1:1.

convert mols Ag to grams. grams = mols x molar mass Ag.

%Ag = [mass Ag/mass sample]*100
mass sample = 0.1284 g.

Post your work if you gt stuck.