Adult tickets for a play cost $9 and child tickets cost $8. If there were 23 people at a performance and the theater collected $193 from ticket sales, how many children attended the play?
A = number of adults
C = number of children
Set up two equations.
A + C = 23
9A + 8C = 193
Solve the equations simultaneously to find A and C.
C=23-A
9A+8(23-A)=193
9A+184-8A=193
184+A=193
A=9
C=23-A
C=23-9
C=14
14 Children attended the play
Joe Keeps only $5-bills and $20-bills in his piggy bank. If he has 216bills that worth $2865, how many $5- bills are in the bank
The Jurassic Zoo charges $13
for each adult admission and $5
for each child. The total bill for the 152
people from a school trip was $1096
.
How many adults and how many children went to the zoo?
To solve the equations simultaneously, we can use either substitution or elimination method. Let's use the elimination method in this case.
Start with the equations:
A + C = 23
9A + 8C = 193
Multiply the first equation by 8 to make the coefficients of C the same in both equations:
8A + 8C = 184
Now, subtract the modified first equation from the second equation to eliminate C:
(9A + 8C) - (8A + 8C) = 193 - 184
A = 9
Substitute A = 9 back into the first equation to solve for C:
9 + C = 23
C = 23 - 9
C = 14
Therefore, there were 14 children who attended the play.