Georgia Connections Academy is selling tickets to its Spring Fling. Adult tickets cost $4 and student tickets cost $2.50. The school makes $2,820. Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold.

(7 points)
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Write an equation that represents this situation to find the cost of all adult and student tickets sold. Use the variable s for student tickets and a for adult tickets sold.

Response area a + Response area s = Response area

900 tickets are sold for the spring fling. Write an equation to represent this situation.

a + Response area = Response area

Use the above system of equations to determine how many adult and student tickets were sold.

Response area adult tickets and Response area student tickets were sold.

Responses - s , 520 , 309 , 900 , 510 , 2820 , 380 , 390 , 4 , 2.50 , a , 591 , 6.5

The equation that represents the cost of all adult and student tickets sold is:

4a + 2.50s = 2820

The equation to represent the situation where 900 tickets are sold is:

a + s = 900

Using the system of equations above, the number of adult tickets sold is 520 and the number of student tickets sold is 380.

Therefore, 520 adult tickets and 380 student tickets were sold.

that was wrong

I apologize for the incorrect response. To find the cost of all adult and student tickets sold, the correct equation is:

4a + 2.50s = 2820

For the situation where 900 tickets are sold, the correct equation is:

a + s = 900

Using this system of equations, the correct response is that 591 adult tickets and 309 student tickets were sold.

The equation that represents the situation to find the cost of all adult and student tickets sold is:

4a + 2.5s = 2820

The equation to represent the situation where 900 tickets are sold for the spring fling is:

a + s = 900

Using the given system of equations, we can determine the number of adult and student tickets sold.

Let's solve the system of equations:

4a + 2.5s = 2820
a + s = 900

To solve the system, we can use substitution or elimination method. Let's use the elimination method.

Multiply the second equation by 4 to eliminate variable 'a'.

4(a + s) = 4(900)
4a + 4s = 3600

Now, subtract this equation from the first equation:

4a + 2.5s - (4a + 4s) = 2820 - 3600
-1.5s = -780
s = -780 / -1.5
s = 520

Substituting this value of 's' into the second equation:

a + 520 = 900
a = 900 - 520
a = 380

Therefore, 380 adult tickets and 520 student tickets were sold.

The equation that represents the cost of all adult and student tickets sold is:

4a + 2.50s = 2820

The equation to represent the situation where 900 tickets are sold for the Spring Fling is:

a + s = 900

To determine how many adult and student tickets were sold, we need to solve the system of equations:

4a + 2.50s = 2820
a + s = 900

From here, we can use various methods of solving simultaneous equations, such as substitution or elimination, to find the values of a and s.