One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products?
In this reaction, bromine (Br2) and potassium chloride (KCI) combine to form two products: potassium bromide (KBr) and chlorine (Cl2).
First, let's calculate the number of atoms in one molecule of each compound:
- In one molecule of bromine (Br2), there are 2 bromine atoms.
- In one molecule of potassium chloride (KCI), there is 1 potassium atom (K) and 1 chlorine atom (Cl).
Now, let's calculate the number of atoms in the products:
- In two molecules of potassium bromide (KBr), there are 2 potassium atoms (2K) and 2 bromine atoms (2Br).
- In two molecules of chlorine (Cl2), there are 4 chlorine atoms (4Cl).
Therefore, the products contain a total of:
2K + 2Br + 4Cl = 2 potassium atoms + 2 bromine atoms + 4 chlorine atoms = 8 atoms.