One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) Combine in a reaction. How many Atoms are in the product?
1. two.
2. four.
3. six.
4. three
The reaction between one molecule of bromine (Br2) and two molecules of potassium chloride (KCI) forms two products. The balanced equation for this reaction is:
Br2 + 2KCI -> 2KBr + Cl2
In this equation, the product is 2KBr. Each potassium bromide (KBr) molecule contains 3 atoms (1 potassium atom and 1 bromine atom), so the total number of atoms in the product is 2 molecules of KBr * 3 atoms/molecule = 6 atoms.
Thus, the correct answer is option 3. Six atoms are in the product.
2NaHCO3--Na2CO3 + CO2
Which of the following can be added to the products to balance the equation?
1. O2
2. H2O
3. CH2OH
4. H2
To balance the given equation, we can see that the number of hydrogen atoms (H) on the left side does not match the number on the right side. We can balance this by adding H2O to the products.
The balanced equation would then be:
2NaHCO3 → Na2CO3 + CO2 + H2O
Thus, the correct answer is option 2. H2O can be added to balance the equation.
Copper (CU) reacts with sulfur (S) to form copper sulfide. a scientist adds 12.7 grams of Cu to 3.2 grams of S to start the reaction, in this reaction all the copper and all the sulfur react. Before running the experiment the scientist expected the products of the reaction will be a total of 15.9 grams of copper sulfide. (Cu2S). In 1-2 sentences explain the law that the scientist used to predict that the product of the reaction would be 15.9 grams of copper sulfide?
The scientist used the Law of Conservation of Mass, which states that mass is neither created nor destroyed in a chemical reaction, to predict that the total mass of the copper sulfide product would be equal to the combined mass of copper and sulfur used in the reaction.
To determine the number of atoms in the product, we need to first understand the reaction equation for the combination of one molecule of bromine (Br2) and two molecules of potassium chloride (KCI).
The reaction equation is as follows:
1 Br2 + 2 KCI -> 2 KBr + 1 Cl2
From the equation, we can see that one molecule of Br2 reacts with two molecules of KCI to form two molecules of KBr and one molecule of Cl2.
Now, let's count the number of atoms in the product.
In two molecules of KBr, there are:
- 2 potassium atoms (2 K)
- 2 bromine atoms (2 Br)
In one molecule of Cl2, there are:
- 2 chlorine atoms (2 Cl)
Adding them up, we get a total of 2 + 2 + 2 = 6 atoms in the product.
Therefore, the correct answer is 3. six.
To determine the number of atoms in the product, we need to calculate the total number of atoms present in the reactants and account for any changes that occur during the reaction.
In this reaction, one molecule of bromine (Br2) reacts with two molecules of potassium chloride (KCI).
First, let's determine the number of atoms in each reactant:
- One molecule of Br2 contains 2 bromine atoms (2 Br).
- Two molecules of KCI contain 2 potassium atoms (2 K) and 2 chlorine atoms (2 Cl).
Now, let's look at the reaction equation again:
Br2 + 2 KCI → 2 KBr + Cl2
In the product, we have two molecules of potassium bromide (KBr) and one molecule of chlorine (Cl2).
Each molecule of KBr contains 1 potassium atom (1 K) and 1 bromine atom (1 Br).
The molecule of Cl2 contains 2 chlorine atoms (2 Cl).
So, the total number of atoms in the product is:
- 2 K atoms
- 2 Br atoms
- 2 Cl atoms
Adding these together, we find that there are 6 atoms in the product.
Therefore, the correct answer is option 3. Six atoms.