In the ionic bond of Na + Br, how many electrons will Na transfer to Br?
Na will transfer one electron to Br.
In the ionic bond between Na (sodium) and Br (bromine), sodium will transfer one electron to bromine.
To determine the number of electrons that sodium (Na) will transfer to bromine (Br) in an ionic bond, we need to look at their electron configurations.
Sodium has an atomic number of 11, meaning it has 11 electrons. The electron configuration of sodium is 1s² 2s² 2p⁶ 3s¹.
Bromine has an atomic number of 35, so it has 35 electrons. The electron configuration of bromine is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁵.
When two elements bond ionically, one element loses electrons to form a positively charged ion (cation), while the other element gains the electrons to form a negatively charged ion (anion).
In this case, sodium is in Group 1 of the periodic table and readily loses one electron to achieve a stable electron configuration like that of a noble gas (in this case, neon). Therefore, sodium will transfer one electron to bromine.
So, in the ionic bond between Na and Br, Na will transfer one electron to Br.