A point is 2 and a die is thrown what is the probability of getting a head and a perfect square
To find the probability of getting a head and a perfect square when throwing a die, we need to calculate the number of favorable outcomes (head and a perfect square) divided by the number of possible outcomes.
There are 2 possible outcomes for the coin: head or tail.
There are 6 possible outcomes for the die: 1, 2, 3, 4, 5, or 6.
To get a favorable outcome, we need to get a head (1 outcome) and a perfect square (2 outcomes: 4 or 6).
Therefore, the number of favorable outcomes is 1 * 2 = 2.
The number of possible outcomes is 2 * 6 = 12.
The probability of getting a head and a perfect square is 2/12, which simplifies to 1/6.
To calculate the probability of getting a head and a perfect square when a die is thrown, we need to analyze two independent events:
1. The probability of getting a head from a point: Since a point is given as 2, there are only two options for the outcome - a head or a tail. Therefore, the probability of getting a head is 1 out of 2, or 1/2.
2. The probability of getting a perfect square from a die: A standard die has six sides, numbered from 1 to 6. Out of these numbers, only 4 (1, 4, 4, and 6) are perfect squares (1=1^2, 4=2^2). So, the probability of rolling a perfect square on a die is 4 out of 6, or 4/6.
Since both events are independent, we can calculate the probability of both events occurring by multiplying their individual probabilities:
Probability of getting a head and a perfect square = Probability of getting a head * Probability of getting a perfect square
= 1/2 * 4/6
= 4/12
= 1/3
Therefore, the probability of getting a head and a perfect square when a die is thrown is 1/3.
To find the probability of getting a head and a perfect square when a die is thrown, we first need to determine the total number of outcomes and the favorable outcomes.
Total number of outcomes when throwing a die: The dice has 6 faces numbered from 1 to 6, so the total number of outcomes is 6.
Favorable outcomes:
1. Getting a head: Since no information is provided about the presence of a coin, let's assume that a fair coin is tossed along with the die. In this case, we have 2 possible outcomes for the coin: heads (H) or tails (T).
2. Getting a perfect square: Out of the 6 faces of the die, the perfect square numbers are 4 and 6 (2^2 and 3^2). So, there are 2 favorable outcomes for getting a perfect square.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of outcomes:
Probability = (Number of favorable outcomes) / (Total number of outcomes)
Probability = (Number of favorable outcomes) / 6
Number of favorable outcomes = 1 (getting a head) * 2 (getting a perfect square) = 2
Substituting the values:
Probability = 2 / 6
Probability = 1 / 3
Therefore, the probability of getting a head and a perfect square when throwing a die is 1/3.